Given your restrictions I'd probably pick [ x * y for x,y in izip(a,b) ] (note the change to ``izip``). But maybe you do not really need lists at all...
You can also do c = (array(a)*array(b)).tolist() which is nice and explicit but builds 3 unnecessary arrays. Alan Isaac _______________________________________________ Numpy-discussion mailing list Numpy-discussion@scipy.org http://projects.scipy.org/mailman/listinfo/numpy-discussion
