On Wednesday 21 January 2009 14:57:59 Neal Becker wrote:
> ublas::vector<T> func (numpy::array_from_py<T>::type const&)
>
> But not for a function that modifies it arg in-place (& instead of const&):
>
> void func (numpy::array_from_py<T>::type &)
^^^^
Use void func (numpy::array_from_py<T>::type )
Why does this work? It is a tradeoff I had to make; I chose to use python
conventions rather than C++ conventions. Essentially, what is passed back to
you is a reference to the numpy array. Any copies you make of it are actually
copies of the reference, not of the actual array. This simplifies the code
quite a bit while maintaining the reference semantics that python programmers
use.
See dump_vec in decco.cc (the example module) for an example.
Regards,
Ravi
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