Hello, this is probably one of those questions that is going to seem simple after reading responses...
I'm trying to get the original array indices out of a row number from a reshaped array... shouldn't this be possible somehow? import numpy as np a = np.ones((3,5,10)) #for testing, I've done the following: a[0,:,:5] = np.eye(5,5)*1 a[1,:,:5] = np.eye(5,5)*10 a[2,:,:5] = np.eye(5,5)*20 #Ok, so I reshape the array: b = a.reshape(15,10) #now I want to be able to 'back out' the original shape indices from the row number of the new array. #I thought I could do something like this: d0,d1,d2 = a.shape new_d0 = row/d1 new_d1 = row/d0 #But it doesn't quite work... any suggestions as to what I am missing? -- View this message in context: http://www.nabble.com/probably-simple%2C-reverse-a-reshape...-tp22171584p22171584.html Sent from the Numpy-discussion mailing list archive at Nabble.com. _______________________________________________ Numpy-discussion mailing list Numpy-discussion@scipy.org http://projects.scipy.org/mailman/listinfo/numpy-discussion
