On 3/18/2009 7:30 PM, Thomas Robitaille wrote:
> import numpy as np
> arr1 = np.array(['a','b','c'])
> arr2 = np.array(['d','e','f'])
>
> I would like to produce a third array that would contain
> ['ad','be','cf']. Is there an efficient way to do this? I could do
> this element by element, but I need a faster method, as I need to do
> this on arrays with several million elements.
>>> arr1 = np.array(['a','b','c'])
>>> arr2 = np.array(['d','e','f'])
>>> arr3 = np.zeros(6, dtype='|S1')
>>> arr3[::2] = arr1
>>> arr3[1::2] = arr2
>>> arr3.view(dtype='|S2')
array(['ad', 'be', 'cf'],
dtype='|S2')
Does this help?
Sturla Molden
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