Andrea Gavana wrote:
> I have a list of integers, like this one:
> 
> indices = [1,2,3,4,5,6,7,8,9,255,256,257,258,10001,10002,10003,10004]
> 
>>From this list, I would like to find out which values are consecutive
> and store them in another list of tuples (begin_consecutive,
> end_consecutive) or a simple list: as an example, the previous list
> will become:
> 
> new_list = [(1, 9), (255, 258), (10001, 10004)]

Is this faster?

In [102]: indices = 
np.array([1,2,3,4,5,6,7,8,9,255,256,257,258,10001,10002,10003,10004,sys.maxint])

In [103]: breaks = np.diff(indices) != 1

In [104]: zip(indices[np.r_[True, breaks[:-1]]], indices[breaks])
Out[104]: [(1, 9), (255, 258), (10001, 10004)]



-Chris



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