Thank you Neil Martinsen-Burrell and Scott Sinclair for your answers. :) It's exactly what i wanted to know. I will use hstack and vstack to "resize" my array. Have a nice day.
--- On Wed, 6/17/09, Scott Sinclair <[email protected]> wrote: The resize method of ndarray is currently broken when the 'order' keyword is specified, which is why you get the SystemError http://projects.scipy.org/numpy/ticket/840 It's also worth knowing that the resize function and the ndarray resize method both behave a little differently. Compare: http://docs.scipy.org/doc/numpy/reference/generated/numpy.ndarray.resize.html and http://docs.scipy.org/doc/numpy/reference/generated/numpy.resize.html Basically, the data in your original array is inserted into the new array in the one dimensional order that it's stored in memory and any remaining space is filled with repeats of the data (resize function) or packed with zero's (resize array method). # resize function >>> import numpy as np >>> a = np.array([[1, 2],[3, 4]]) >>> print a [[1 2] [3 4]] >>> print np.resize(a, (3,3)) [[1, 2, 3], [4, 1, 2], [3, 4, 1]]) #resize array method >>> b = np.array([[1, 2],[3, 4]]) >>> print b [[1 2] [3 4]] >>> b.resize((3,3)) >>> print b [[1 2 3] [4 0 0] [0 0 0]] Neil's response gives you what you want in this case. Cheers, Scott _______________________________________________ Numpy-discussion mailing list [email protected] http://mail.scipy.org/mailman/listinfo/numpy-discussion
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