> Does numpy have functions to convert between e.g. an array of uint32
> and
> uint8, where the uint32 array is a packed version of the uint8 array
> (selecting little/big endian)?
You could use the ndarray constructor to look at the memory differently:
In : a = numpy.arange(240, 260, dtype=numpy.uint32)
In : a
Out:
array([240, 241, 242, 243, 244, 245, 246, 247, 248, 249, 250, 251, 252,
253, 254, 255, 256, 257, 258, 259], dtype=uint32)
In : b = numpy.ndarray(shape=(len(a)*4,), dtype=numpy.uint8, buffer=a)
In : b
Out:
array([240, 0, 0, 0, 241, 0, 0, 0, 242, 0, 0, 0, 243,
0, 0, 0, 244, 0, 0, 0, 245, 0, 0, 0, 246, 0,
0, 0, 247, 0, 0, 0, 248, 0, 0, 0, 249, 0, 0,
0, 250, 0, 0, 0, 251, 0, 0, 0, 252, 0, 0, 0,
253, 0, 0, 0, 254, 0, 0, 0, 255, 0, 0, 0, 0,
1, 0, 0, 1, 1, 0, 0, 2, 1, 0, 0, 3, 1,
0, 0], dtype=uint8)
I assume for selecting little/big-endian going the other way, you
could use the other methods of specifying dtypes that allow for byte-
order descriptors. (Like dtype objects or the format strings.)
Zach
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