On Sun, Feb 28, 2010 at 7:35 PM, Ian Mallett <geometr...@gmail.com> wrote:
> On Sun, Feb 28, 2010 at 6:31 PM, Charles R Harris < > charlesr.har...@gmail.com> wrote: > >> As I understand it, you want *different* matrices applied to each vector? > > Nope--I need the same matrix applied to each vector. > > Because 3D translation matrices must, if I understand correctly be 4x4, the > vectors must first be changed to length 4 (adding a 1 for the last term). > Then, the matrices would be applied. Then, the resulting n*4 array would be > converted back into a n*3 array (simply by dropping the last term). > > Why not just add a vector to get translation? There is no need to go the homogeneous form. Or you can just leave the vectors at length 4 and use a slice to access the first three components. That way you can leave the ones in place. Chuck
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