On Fri, Mar 12, 2010 at 12:52, gerardo.berbeglia <gberbeg...@gmail.com> wrote:
>
> Hello,
>
> I want to "divide" an n x n (2-dimension) numpy array matrix A by a n
> (1-dimension) array d as follows:
>
> Take n = 2.
> Let A= 2 3
> 1 10
> and let d = [ 3 2 ]
> Then i would like to have "A/d" = 2/3 3/3
> 1/2 10/2
In [2]: import numpy
In [3]: a = numpy.array([[2.0, 3.0], [1.0, 10.0]])
In [4]: a
Out[4]:
array([[ 2., 3.],
[ 1., 10.]])
In [5]: d = numpy.array([[3.0], [2.0]])
In [6]: d
Out[6]:
array([[ 3.],
[ 2.]])
In [7]: a / d
Out[7]:
array([[ 0.66666667, 1. ],
[ 0.5 , 5. ]])
--
Robert Kern
"I have come to believe that the whole world is an enigma, a harmless
enigma that is made terrible by our own mad attempt to interpret it as
though it had an underlying truth."
-- Umberto Eco
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