Hi, actually, I meant to reply to Mark's mail, as I used his solution ;)
Thanks! On 06/08/2010 09:21 PM, Gökhan Sever wrote: > If we were at so or ask.scipy I would vote for Mark's solution :) > > Usually in cases like yours, I tend to use the shortest version of the > solutions. > > On Tue, Jun 8, 2010 at 2:08 PM, Andreas Hilboll <li...@hilboll.de > <mailto:li...@hilboll.de>> wrote: > > Hi, > > > newtimes = [times[idx[x][y]] for x in range(2) for y in range(2)] > > np.array(newtimes).reshape(2,2) > > array([[104, 102], > > [103, 101]]) > > Great, thanks a lot! > > Cheers, > > Andreas. > > _______________________________________________ > NumPy-Discussion mailing list > NumPy-Discussion@scipy.org <mailto:NumPy-Discussion@scipy.org> > http://mail.scipy.org/mailman/listinfo/numpy-discussion > > > > > -- > Gökhan > > > > _______________________________________________ > NumPy-Discussion mailing list > NumPy-Discussion@scipy.org > http://mail.scipy.org/mailman/listinfo/numpy-discussion _______________________________________________ NumPy-Discussion mailing list NumPy-Discussion@scipy.org http://mail.scipy.org/mailman/listinfo/numpy-discussion
