Hi, I was always using something like
abs(x-y) < eps or (abs(x-y) < eps).all() but today I needed to also make sure this works for larger numbers, where I need to compare relative errors, so I found this: http://www.cygnus-software.com/papers/comparingfloats/comparingfloats.htm and wrote this: def feq(a, b, max_relative_error=1e-12, max_absolute_error=1e-12): a = float(a) b = float(b) # if the numbers are close enough (absolutely), then they are equal if abs(a-b) < max_absolute_error: return True # if not, they can still be equal if their relative error is small if abs(b) > abs(a): relative_error = abs((a-b)/b) else: relative_error = abs((a-b)/a) return relative_error <= max_relative_error Is there any function in numpy, that implements this? Or maybe even the better, integer based version, as referenced in the link above? I need this in tests, where I calculate something on some mesh, then compare to the correct solution projected on some other mesh, so I have to deal with accuracy issues. Ondrej _______________________________________________ NumPy-Discussion mailing list NumPy-Discussion@scipy.org http://mail.scipy.org/mailman/listinfo/numpy-discussion
