On Mon, Jul 26, 2010 at 5:48 PM, Alan G Isaac <ais...@american.edu> wrote: > On 7/26/2010 12:45 PM, Skipper Seabold wrote: >> Right now np.linalg.det does not handle scalars or 1d (scalar) arrays. > > I don't have a real opinion on changing this, but I am curious > to know the use case, as the current behavior seems
Use case is just so that I can have less atleast_2d's in my code, since checks are done in linalg.det anyway. > a) correct and b) to provide an error check. > Isn't the determinant defined for a scalar b such that det(b) == det([b]) == det([[b]])? The error check is redundant I think if the determinant is defined for a scalar (if not then shouldn't det([[b]]) fail?). Check if something is 2d. Check if something is square. Since a square array is by definition 2d, if you replace asarray then the check for 2d with atleast_2d, you can handle the scalar case and then go on to check if it's square. Basically, it saves a tiny bit of time in det and saves me from writing atleast_2d. Skipper _______________________________________________ NumPy-Discussion mailing list NumPy-Discussion@scipy.org http://mail.scipy.org/mailman/listinfo/numpy-discussion