Wed, 27 Oct 2010 09:44:59 -0400, Skipper Seabold wrote:
[clip]
> In [35]: timeit np.any(a!=b)
[clip]
> It seems to at least take less time when the difference is at the
> "beginning," though I'm sure there could be exceptions.

It performs all the comparisons to create a temporary boolean array.
any() does return when it sees the first True, but this is not full
short-circuiting.

-- 
Pauli Virtanen

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