Hi all, I have this problem: Given some point draw a circle centered in this point with radius r. I'm doing that using numpy this way (Snippet code from here [1]):
>>> # Create the initial black and white image >>> import numpy as np >>> from scipy import ndimage >>> a = np.zeros((512, 512)).astype(uint8) #unsigned integer type needed by >>> watershed >>> y, x = np.ogrid[0:512, 0:512] >>> m1 = ((y-200)**2 + (x-100)**2 < 30**2) >>> m2 = ((y-350)**2 + (x-400)**2 < 20**2) >>> m3 = ((y-260)**2 + (x-200)**2 < 20**2) >>> a[m1+m2+m3]=1 >>> imshow(a, cmap = cm.gray)# left plot in the image above The problem is that it have to evaluate all values from 0 to image size (in snippet, from 0 to 512 in X and Y dimensions). There is a faster way of doing that? Without evaluate all that values? For example: only evaluate from 0 to 30, in a circle centered in (0, 0) with radius 30. Thanks! Thiago Franco de Moraes [1] - http://www.scipy.org/Cookbook/Watershed _______________________________________________ NumPy-Discussion mailing list NumPy-Discussion@scipy.org http://mail.scipy.org/mailman/listinfo/numpy-discussion
