On Sat, Apr 16, 2011 at 8:39 PM, Forrest Sheng Bao <forrest....@gmail.com> wrote: >>>> a=zeros((3,3)) + eye(3) >>>> a*a > array([[ 1., 0., 0.], > [ 0., 1., 0.], > [ 0., 0., 1.]]) > > Then i assigned a value to one of the element: > >>>> a[1,2]=4 > > Finally, the '*' operator was interpreted as a matrix multiplication > >>>> a*a > array([[ 1., 0., 0.], > [ 0., 1., 16.], > [ 0., 0., 1.]])
That looks like element-wise multiplication to me? (Matrix multiplication would have given you an 8 where you have a 16.) -- Nathaniel _______________________________________________ NumPy-Discussion mailing list NumPy-Discussion@scipy.org http://mail.scipy.org/mailman/listinfo/numpy-discussion
