It'll work, it is equivalent to the suggestion I made in my previous post with the f_inplace wrapper function (and it has the same drawback that numpy will allocate temporary memory, which wouldn't be the case if f was working in-place directly, by implementing it as "arr *= 2").
Note that you don't need to write x[:] * 2, you can write x * 2 directly. -=- Olivier 2011/10/1 David Froger <david.fro...@gmail.com> > > Thanks everybody for the different solutions proposed, I really appreciate. > What about this solution? So simple that I didn't think to it... > > import numpy as np > from numpy import * > > def f(arr): > return arr*2 > > a = array( [1,1,1] ) > b = array( [2,2,2] ) > c = array( [3,3,3] ) > d = array( [4,4,4] ) > > for x in (a,b,c,d): > x[:] = x[:]*2 > #instead of: x = x*2 > > print a > print b > print c > print d > -- > _______________________________________________ > NumPy-Discussion mailing list > NumPy-Discussion@scipy.org > http://mail.scipy.org/mailman/listinfo/numpy-discussion >
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