Hi, Sorry for my continued confusion here. This is numpy 1.6.1 on windows XP 32 bit.
In [2]: np.finfo(np.float96).nmant Out[2]: 52 In [3]: np.finfo(np.float96).nexp Out[3]: 15 In [4]: np.finfo(np.float64).nmant Out[4]: 52 In [5]: np.finfo(np.float64).nexp Out[5]: 11 If there are 52 bits of precision, 2**53+1 should not be representable, and sure enough: In [6]: np.float96(2**53)+1 Out[6]: 9007199254740992.0 In [7]: np.float64(2**53)+1 Out[7]: 9007199254740992.0 If the nexp is right, the max should be higher for the float96 type: In [9]: np.finfo(np.float64).max Out[9]: 1.7976931348623157e+308 In [10]: np.finfo(np.float96).max Out[10]: 1.#INF I see that long double in C is 12 bytes wide, and double is the usual 8 bytes. So - now I am not sure what this float96 is. I was expecting 80 bit extended precision, but it doesn't look right for that... Does anyone know what representation this is? Thanks a lot, Matthew _______________________________________________ NumPy-Discussion mailing list NumPy-Discussion@scipy.org http://mail.scipy.org/mailman/listinfo/numpy-discussion
