Excellent, thank you.
I just realised this does not work with my data because of the extra
dimension.
I have a mask that matches my 2-dimensional array but my data is for every
hour over a month so the arrays do not match. Is there a way to make them
match or mask each time?
thanks again
This is some of my code:
for ncfile in files:
if ncfile[-3:]=='.nc':
print "dealing with ncfiles:",
path+ncfile
ncfile=os.path.join(path,ncfile)
ncfile=Dataset(ncfile, 'r+', 'NETCDF4')
TSFC=ncfile.variables['T_SFC'][:]
TIME=ncfile.variables['time'][:]
fillvalue=ncfile.variables['T_SFC']._FillValue
TSFC=MA.masked_values(TSFC, fillvalue)
ncfile.close()
TSFC=MA.masked_array(TSFC,
mask=newmask.mask)
On Tue, Nov 22, 2011 at 11:21 AM, Olivier Delalleau <sh...@keba.be> wrote:
> If your new array is x, you can use:
>
> numpy.ma.masked_array(x, mask=mask.mask)
>
> -=- Olivier
>
> 2011/11/21 questions anon <questions.a...@gmail.com>
>
>> I am trying to mask one array using another array.
>>
>> I have created a masked array using
>> mask=MA.masked_equal(myarray,
>> 0),
>> that looks something like:
>> [1 - - 1,
>> 1 1 - 1,
>> 1 1 1 1,
>> - 1 - 1]
>>
>> I have an array of values that I want to mask whereever my mask has a a
>> '-'.
>> how do I do this?
>> I have looked at
>> http://www.cawcr.gov.au/bmrc/climdyn/staff/lih/pubs/docs/masks.pdf but
>> the command:
>>
>> d = array(a, mask=c.mask()
>>
>> results in this error:
>> TypeError: 'numpy.ndarray' object is not callable
>>
>> I basically want to do exactly what that article does in that equation.
>>
>> Any feedback will be greatly appreciated.
>>
>> _______________________________________________
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>>
>>
>
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