On Sun, Dec 4, 2011 at 5:30 AM, Didrik Pinte <dpi...@enthought.com> wrote:
> On Sun, Dec 4, 2011 at 6:11 AM, Warren Weckesser
> <warren.weckes...@enthought.com> wrote:
> > In numpy 1.6.1, what's the most straightforward way to convert a
> datetime64
> > to a python datetime.datetime? E.g. I have
> >
> > In [1]: d = datetime64("2011-12-03 12:34:56.75")
> >
> > In [2]: d
> > Out[2]: 2011-12-03 12:34:56.750000
> >
> > I want the same time as a datetime.datetime instance. My best hack so
> far
> > is to parse repr(d) with datetime.datetime.strptime:
> >
> > In [3]: import datetime
> >
> > In [4]: dt = datetime.datetime.strptime(repr(d), "%Y-%m-%d %H:%M:%S.%f")
> >
> > In [5]: dt
> > Out[5]: datetime.datetime(2011, 12, 3, 12, 34, 56, 750000)
> >
> > That works--unless there are no microseconds, in which case ".%f" must be
> > removed from the format string--but there must be a better way.
> >
> > Warren
>
>
> Warren,
>
> You can do that :
>
> In [13]: a = array(["2011-12-03 12:34:56.75"], dtype=datetime64)
>
> In [14]: b = a.astype(object)
>
> In [15]: b[0]
> Out[15]: datetime.datetime(2011, 12, 3, 12, 34, 56, 750000)
>
> Not sure how efficient it is but it works fine.
>
> -- Didrik
>
Thanks, Didrik, that's just what I needed.
Warren
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