I solved using 'rb' instead of 'r' option in the open file task.
Thank you very much.
Il 05/02/2012 19:13, Warren Weckesser ha scritto:
On Sun, Feb 5, 2012 at 12:06 PM, <josef.p...@gmail.com
<mailto:josef.p...@gmail.com>> wrote:
On Sun, Feb 5, 2012 at 12:52 PM, Paolo <p.zaff...@yahoo.it
<mailto:p.zaff...@yahoo.it>> wrote:
How I can do this?
I'm not sure without trying, numpy.loadtxt might be the easier choice
matrix="".join((i.strip() for i in f.readlines()))
I think strip() also removes newlines besides other whitespace
otherwise more explicitly
matrix="".join((i.strip(f.newlines) for i in f.readlines()))
or open the file with mode 'rU' and strip('\n')
Josef
This code:
matrix="".join(f.readlines())
matrix=np.fromstring(matrix, dtype=np.int16)
matrix=matrix.reshape(siz[2],siz[1],siz[0]).T
implies that the data in f is binary, because the 'sep' keyword is not
used in the call to np.fromstring. If that is the case, you should
not use f.readlines() to read the data. Instead, read it as a single
string with f.read(). (Or perhaps read the file with a single call to
np.fromfile()). Also be sure that the file was opened in binary mode
(i.e. f = open(filename, 'rb')).
Warren
Il 05/02/2012 18:47, josef.p...@gmail.com
<mailto:josef.p...@gmail.com> ha scritto:
On Sun, Feb 5, 2012 at 12:39 PM, Paolo <p.zaff...@yahoo.it
<mailto:p.zaff...@yahoo.it>> wrote:
This is my code:
matrix="".join(f.readlines())
my guess would be, that you have to strip the line endings \n
versus \r\n
Josef
matrix=np.fromstring(matrix, dtype=np.int16)
matrix=matrix.reshape(siz[2],siz[1],siz[0]).T
Il 05/02/2012 17:21, Olivier Delalleau ha scritto:
It means there is some of your code that is not entirely
platform-independent. It's not possible to tell you
which part because you didn't provide your code. The
problem may not even be numpy-related.
So you should first look at the current shape of
'matrix', and what are the values of a, b and c, then
see where the discrepancy is, and work from there.
-=- Olivier
Le 5 février 2012 11:16, Paolo Zaffino
<p.zaff...@yahoo.it <mailto:p.zaff...@yahoo.it>> a écrit :
Yes, I understand this but I don't know because on
Linux and Mac it works well.
If the matrix size is different it should be
different indipendently from os type.
Am I wrong?
Thanks for your support!
------------------------------------------------------------------------
*From: * Olivier Delalleau <sh...@keba.be
<mailto:sh...@keba.be>>;
*To: * Discussion of Numerical Python
<numpy-discussion@scipy.org
<mailto:numpy-discussion@scipy.org>>;
*Subject: * Re: [Numpy-discussion] "ValueError:
total size of new array must be unchanged" only on
Windows
*Sent: * Sun, Feb 5, 2012 3:02:44 PM
It should mean that matrix.size != a * b * c.
-=- Olivier
Le 5 février 2012 09:32, Paolo <p.zaff...@yahoo.it>
a écrit :
Hello,
I wrote a function that works on a numpy matrix
and it works fine on Mac
OS and GNU/Linux (I didn't test it on python 3).
Now I have a problem with numpy: the same python
file doesn't work on
Windows (Windows xp, python 2.7 and numpy 2.6.1).
I get this error:
matrix=matrix.reshape(a, b, c)
ValueError: total size of new array must be
unchanged
Why? Do anyone have an idea about this?
Thank you very much.
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