How about the following? exact: numpy.all(a == a[0]) inexact: numpy.allclose(a, a[0])
On Mar 5, 2012, at 2:19 PM, Keith Goodman wrote: > On Mon, Mar 5, 2012 at 11:14 AM, Neal Becker <ndbeck...@gmail.com> wrote: >> What is a simple, efficient way to determine if all elements in an array (in >> my >> case, 1D) are equal? How about close? > > For the exactly equal case, how about: > > I[1] a = np.array([1,1,1,1]) > I[2] np.unique(a).size > O[2] 1 # All equal > > I[3] a = np.array([1,1,1,2]) > I[4] np.unique(a).size > O[4] 2 # All not equal > _______________________________________________ > NumPy-Discussion mailing list > NumPy-Discussion@scipy.org > http://mail.scipy.org/mailman/listinfo/numpy-discussion _______________________________________________ NumPy-Discussion mailing list NumPy-Discussion@scipy.org http://mail.scipy.org/mailman/listinfo/numpy-discussion
