Now I am clear. I guess the vectorized notation speeds up difference
equations describing FIR structures, whereas IIR ones won't benefit.

Francesco Barale wrote:
> 
> Hello everyone,
> 
> After reading the very good post
> http://technicaldiscovery.blogspot.com/2011/06/speeding-up-python-numpy-cython-and.html
> and the book by H. P. Langtangen 'Python scripting for computational
> science' I was trying to speed up the execution of a loop on numpy arrays
> being used to describe a simple difference equation.
> 
> The actual code I am working on involves some more complicated equations,
> but I am having the same exact behavior as described below. To test the
> improvement in speed I wrote the following in vect_try.py:
> 
> #!/usr/bin/python
> import numpy as np
> import matplotlib.pyplot as plt
> 
> dt = 0.02 #time step
> time = np.arange(0,2,dt) #time array
> u = np.sin(2*np.pi*time) #input signal array
> 
> def vect_int(u,y): #vectorized function
>     n = u.size
>     y[1:n] = y[0:n-1] + u[1:n]
>     return y
> 
> def sc_int(u,y): #scalar function
>     y = y + u
>     return y
> 
> def calc_vect(u, func=vect_int):
>     out = np.zeros(u.size)
>     for i in xrange(u.size):
>         out = func(u,out)
>     return out
>        
> def calc_sc(u, func=sc_int):
>     out = np.zeros(u.size)
>     for i in xrange(u.size-1):
>         out[i+1] = func(u[i+1],out[i])
>     return out
> 
> To verify the execution time I've used the timeit function in Ipython:
> 
> import vect_try as vt
> timeit vt.calc_vect(vt.u) --> 1000 loops, best of 3: 494 us per loop
> timeit vt.calc_sc(vt.u) -->10000 loops, best of 3: 92.8 us per loop
> 
> As you can see the scalar implementation looping one item at the time
> (calc_sc) is 494/92.8~5.3 times faster than the vectorized one
> (calc_vect). 
> 
> My problem consists in the fact that I need to iterate the execution of
> vect_int in order for it to operate on all the elements of the input
> array. If I execute vect_int only once, it will only operate on the first
> slice of the vectors leaving the remaining untouched. My understanding was
> that the vector expression y[1:n] = y[0:n-1] + u[1:n] was supposed to
> iterate over all the array, but that's not happening for me. Can anyone
> tell me what I am doing wrong?
> 
> Thanks!
> Francesco
> 
> 

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