On Wed, May 23, 2012 at 4:16 PM, Kathleen M Tacina <
kathleen.m.tac...@nasa.gov> wrote:

> **
> On Wed, 2012-05-23 at 17:31 -0500, Nathaniel Smith wrote:
>
> On Wed, May 23, 2012 at 10:53 PM, Travis Oliphant <tra...@continuum.io> 
> wrote:> To be clear, I'm not opposed to the change, and it looks like we 
> should go forward.>> In my mind it's not about developers vs. users as 
> satisfying users is the whole point.   The purpose of NumPy is not to make 
> its developers happy :-).   But, users also want there to *be* developers on 
> NumPy so developer happiness is not irrelevant.>> In this case, though, there 
> are consequences for users because of the double copy if a user wants to make 
> their code future proof.   We are always trading off predicted 
> user-experiences.    I hope that we all don't have the same perspective on 
> every issue or more than likely their aren't enough voices being heard from 
> real users.
> I'm not really worried about users who have a problem with thedouble-copy. 
> It's a totally legitimate concern, but anyone who hasthat concern has already 
> understood the issues well enough to be ableto take care of themselves, and 
> decided that it's worth the effort tospecial-case this. They can check 
> whether the returned array has .baseset to tell whether it's an array or a 
> view, use a temporary hack tocheck for the secret warning flag in 
> arr.flags.num, check the numpyversion, all sorts of things to get them 
> through the one version wherethis matters. The suggestion in the docs to make 
> a copy is not exactlybinding :-).
> -- Nathaniel
>
>
> As a "real user", if I care about whether an array arr2 is a copy or a
> view, I usually either check arr2.flags.owndata or append copy() to the
> statement that created arr2, e.g., arr2 = arr.diagonal().copy().
>
> Numpy rules on views vs. copies sometimes require a bit of thought, and so
> I'll frequently just check the flags or make a copy instead of thinking.
> (More foolproof :).)
>
>
>

 It seems that there are a number of ways to check if an array is a view.
 Do we have a preferred way in the API that is guaranteed to stay
available?  Or are all of the various methods "here to stay"?
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