There are various ways to repack the pair of arrays into one array. The most universal is probably to use structured array (can repack more than a pair):
x = np.array(zip(a, b), dtype=[('a',int), ('b',int)]) After repacking you can use unique and other numpy methods: xu = np.unique(x) zip(xu['a'], xu['b'], np.bincount(np.searchsorted(xu, x))) [(4, 3, 2), (4, 4, 2), (4, 5, 1), (5, 4, 1)] Val On Tue, Jul 24, 2012 at 5:09 PM, Giuseppe Amatulli < giuseppe.amatu...@gmail.com> wrote: > Hi, > > would like to identify unique pairs of numbers in two arrays o in one > bi-dimensional array, and count the observation > > a_clean=array([4,4,5,4,4,4]) > b_clean=array([3,5,4,4,3,4]) > > and obtain > (4,3,2) > (4,5,1) > (5,4,1) > (4,4,2) > > I solved with tow loops but off course there will be a fast solution > Any idea? > what about using np.unique for one bi-dimensional array? > > In bash I usually unique command > > thanks in advance > Giuseppe > > -- > Giuseppe Amatulli > Web: www.spatial-ecology.net > _______________________________________________ > NumPy-Discussion mailing list > NumPy-Discussion@scipy.org > http://mail.scipy.org/mailman/listinfo/numpy-discussion >
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