Thanks for the answer in Stackoverflow. I checked it out.
Суббота, 4 мая 2013, 21:24 -04:00 от Warren Weckesser <warren.weckes...@gmail.com>: >On 5/4/13, Bakhtiyor Zokhidov < bakhtiyor_zokhi...@mail.ru > wrote: >> >> Hi, >> I have the following code which represents intersected point of each cell in >> the given two points, A(x0,y0) and B(x1,y1). >> >> def intersected_points(x0, x1, y0, y1): >> # slope >> m = (y1 - y0 )/( x1 - x0) >> # Boundary of the selected points >> x_ceil = ceil( min (x0, x1 )) >> x_floor = floor( max(x0, x1)) >> y_ceil = ceil( min(y0, y1)) >> y_floor = floor( max(y0, y1)) >> # calculate all intersected x coordinate >> ax = [] >> for x in arange(x_ceil, x_floor + 1, 1): >> ax.append([ x, m * ( x - x0 ) + y0 ]) >> # calculate all intersected y coordinate >> for y in arange(y_ceil, y_floor + 1, 1): >> ax.append([ ( y - y0 ) * ( 1./m ) + x0, y ]) >> return ax >> >> Sample values: intersected_points(1.5,4.4,0.5,4.1) >> Output: [[2.0, 1.1206896551724137], [3.0, 2.3620689655172411], [4.0, >> 3.6034482758620685], [1.9027777777777779, 1.0], [2.7083333333333335, 2.0], >> [3.5138888888888893, 3.0], [4.3194444444444446, 4.0]] >> >> The output I got is unsorted values, so, for each cell coordinates, where >> line crosses: >> BUT, The result I want to get should be something in increased orders >> like: (x0,y0), (x1,y1), (x2,y2), (x3,y3) >> where x0, y0 - intial, x1,y1 - final point. Other values are intersected >> line coordinates! >> >> Any answers will be appreciated, >> >> -- Bakhtiyor Zokhidov > > >You also asked this question on stackoverflow >( >http://stackoverflow.com/questions/16377826/distance-for-each-intersected-points-of-a-line-in-increased-order-in-2d-coordina > ). > I've posted an answer there. > >Warren >_______________________________________________ >NumPy-Discussion mailing list >NumPy-Discussion@scipy.org >http://mail.scipy.org/mailman/listinfo/numpy-discussion
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