On Fri, Dec 20, 2013 at 11:19:49AM +0000, Oscar Benjamin wrote: > Date: Fri, 20 Dec 2013 11:19:49 +0000 > From: Oscar Benjamin <oscar.j.benja...@gmail.com> > To: Discussion of Numerical Python <numpy-discussion@scipy.org> > Subject: Re: [Numpy-discussion] Array search considering order > > On 19 December 2013 16:49, Andrei Rozanski <and...@ruivo.org> wrote: > > > > Sorry if I was not clear enough. > > The SO question is alike what I want. However, in my problem, Im not sure > > if there will be only one occurence. > > What I do expect is: > > Given one array (big one), to retrieve indexes for "query array" occurences. > > Something like that: > > > > array1(big one) - 1,2,3,4,5,6,7,1,2,3,4,5,7,8,9,1,2,3,4,5,6,7,8 > > array2(query) - 1,2,3 > > array3(another query) - 8,7,6 > > > > result (array1 versus array2) - 0,7,15 (position for match) > > result (array1 versus array3) - no matches > > If you look more closely at the SO question you'll see that it does > answer your problem. The top-rated answer shows how to get an boolean > array indicating where the matches are. In your case that would be > > [True, False, False, False, False, False, False, True, False, False, > False, False, False, False, False, True, False, False, False, False, > False] > > Now just use the numpy.where function to get the indices of the True > value from this array. > > > Oscar > _______________________________________________ > NumPy-Discussion mailing list > NumPy-Discussion@scipy.org > http://mail.scipy.org/mailman/listinfo/numpy-discussion
Hi Oscar, Thank you for the help. Indeed. My lack of knowledge on numpy functions didnt aloud my to get that. That works for me. best regards. _______________________________________________ NumPy-Discussion mailing list NumPy-Discussion@scipy.org http://mail.scipy.org/mailman/listinfo/numpy-discussion
