Hi,
On Tue, Apr 15, 2014 at 12:34 AM, Julian Taylor
<jtaylor.deb...@googlemail.com> wrote:
> On Tue, Apr 15, 2014 at 4:30 AM, Matthew Brett <matthew.br...@gmail.com>
> wrote:
>>
>> It looks as though mingw-w64 is at fault, and I was confused (still
>> am) because of the different behavior with double and a constant:
>>
>> #include <stdio.h>
>> #include <math.h>
>>
>> int main() {
>> double z, i = -0.0;
>> printf("With double %f=%f, with constant=%f\n",
>> i, expm1(i), expm1(-0.));
>> }
>>
>> gives:
>>
>> With double -0.000000=0.000000, with constant=-0.000000
>>
>> That was ugly to track down.
>>
>> What is the right way to work round this (using the numpy version
>> instead of the system version I suppose)?
>>
>
> The right way is to file a bug at mingw and get it fixed at the source.
http://sourceforge.net/p/mingw-w64/code/6594/
> Additionally as this time npymath seems to be better (thats 3 bugs in
> npymath vs 1 in mingw on my scoreboard) one could use the mingw
> preprocessor define instead of HAVE_EXP1M to select this function from
> npymath.
Sorry to be slow - could you unpack what you mean in this paragraph?
Is there a way to force use of the numpy version of the function using
environment variables or similar?
Cheers,
Matthew
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