Since you use 0 and 1, SUM() should do the trick shouldn't it?

Or am I misinterpreting your question?

mysql> create table hotel ( brekky tinyint, confer tinyint );
Query OK, 0 rows affected (0.30 sec)

mysql> insert into hotel ( brekky, confer ) values (0,1), (1,1), (0,0),
(0,1), (0,1) ;
Query OK, 5 rows affected (0.09 sec)
Records: 5  Duplicates: 0  Warnings: 0

mysql> select sum(brekky), sum(confer) from hotel ;
+-------------+-------------+
| sum(brekky) | sum(confer) |
+-------------+-------------+
|           1 |           4 |
+-------------+-------------+
1 row in set (0.13 sec)

On Fri, Feb 13, 2009 at 9:23 PM, renjith das <[email protected]> wrote:

> Hi
>         Do you have any relation between these two tables? . I mean have
> you any field in both table to relate each other.
>
> If yes you can use the left join to join these two tables.
>
> Regards
> Renjith
>
>
> On Fri, Feb 13, 2009 at 5:12 PM, Olivia Brown <[email protected]> wrote:
>
>> Hi,
>>
>> I have a MySql database that contains a 'motels' table. One of the fields
>> in the table is 'breakfast_available' and this contains an integer (1 for
>> yes, 0 for no)
>> The other field in this table is 'conference_facilities' which also stores
>> an integer value 1 or 0 like the other field above.
>>
>> I would like to setup one MySql query that will display this number of
>> motels have breakfast available (breakfast_available = 1) and this number of
>> motels provide conference facilities (conference_facilities = 1)
>>
>>
>>
>
> >
>

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