Hi, I'm sorry this feature is not available. You would need to set a property "childCount" explicitly.
Could you explain the use case please? Regards, Thomas On 20/07/16 15:48, "Milan Milanov" <mila...@null.net> wrote: >Hello there, > >I¹m trying to order some nodes by how many child nodes they have and i¹ve >stumped upon a headache. >My query looks like this: > >"SELECT * FROM 'nt:hierarchyNode' AS node >WHERE ISCHILDNODE(node, Œ/some/given/path¹) >ORDER BY 'jcr:primaryType' DESC, LENGTH(node) ASC² > >This is taking all child nodes of a given node and ordering the >nt:folders first (before the nt:files). However, the >LENGTH(node) does not seem to be doing what I want it to do (count the >number of children). Is there anything >oak-specific that could solve my problem, like Modeshape¹s CHILDCOUNT() >or like having a custom function >somehow? > >Kind regards, >Milan Milanov
