Olivier,

Olivier Andrieu wrote:
> On 5/7/07, Hugo Ferreira <[EMAIL PROTECTED]> wrote:
>> Hello,
>>
>> Olivier Andrieu wrote:
>>> On 5/7/07, Hugo Ferreira <[EMAIL PROTECTED]> wrote:

snip...
>> My understanding is that (imperative) Skip lists have the performance of
>> balanced trees but also allow for iterating over all elements in O(N),
>> which is what I want (but not necessarily in order).
> 
> Balanced trees also allow for iterating over all elements in O(N) !
> 

Ok, I confess my ignorance. Apologies if this is a stupid question.  How
is this possible?

To reach all leaf nodes don't I have to visit each non-leaf node at
least once (at most twice). And aren't their SUM(i=0 to log(N)) 2^i
nodes in the tree? If so don't I have to visit all
SUM(i=0 to log(N)) 2^i nodes?


Note that I have to backtrack on this structure and need to use a simple
backtracking iterator hence my considering skip-lists (I need only keep
one reference to the current list position and visit each such
element once).

> The advantage of skip lists IMO is that they are easy to understand
> and implement, that's all.
> 

Well, for the doubly linked list version I agree. The use of the
sentinel references demands some care though. BTW are you aware that
their is a deterministic version of the skip list?

Regards,
Hugo F.


> > 
> 


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