tor, 05 03 2009 kl. 16:04 +0100, skrev Alois Schlögl: > Or can You think of any reasonable problem, when mean should propagate > the NaN's ? I can not. Consequently, there is no need to have both > nanmean and mean.
I guess this depends on how you interpret NaN. I think it makes sense to skip NA (not available) when computing mean values. But if NaN is the result of some faulty calculation somewhere in your program, then it can be nice to see the NaN's propagate. Otherwise you might never notice you had a bug. Søren ------------------------------------------------------------------------------ Open Source Business Conference (OSBC), March 24-25, 2009, San Francisco, CA -OSBC tackles the biggest issue in open source: Open Sourcing the Enterprise -Strategies to boost innovation and cut costs with open source participation -Receive a $600 discount off the registration fee with the source code: SFAD http://p.sf.net/sfu/XcvMzF8H _______________________________________________ Octave-dev mailing list [email protected] https://lists.sourceforge.net/lists/listinfo/octave-dev
