manolo, jesús, gracias por las fotocopias la ecuación clave es k*Q=1 que define la situacion de máxima transferencia de potencia y coincide con el aploplamiento crítico :-)
a ver donde llego... gracias de nuevo, eduardo
Version 4
SHEET 1 880 680
WIRE -1072 -160 -1072 -192
WIRE -1056 -192 -1072 -192
WIRE -976 -192 -1056 -192
WIRE -832 -192 -912 -192
WIRE -832 -144 -832 -192
WIRE -832 -64 -832 -80
WIRE -784 -192 -832 -192
WIRE -736 -192 -784 -192
WIRE -736 -160 -736 -192
WIRE -736 -64 -736 -80
WIRE -640 -192 -736 -192
WIRE -512 -192 -576 -192
WIRE -512 -144 -512 -192
WIRE -512 -64 -512 -80
WIRE -448 -192 -512 -192
WIRE -400 -192 -448 -192
WIRE -400 -160 -400 -192
WIRE -400 -64 -400 -80
WIRE -304 -192 -400 -192
WIRE -144 -192 -240 -192
WIRE -144 -160 -144 -192
WIRE -144 -64 -144 -80
FLAG -1072 -80 0
FLAG -832 -64 0
FLAG -736 -64 0
FLAG -512 -64 0
FLAG -400 -64 0
FLAG -144 -64 0
FLAG -144 -192 Vout
FLAG -784 -192 VM1
FLAG -448 -192 VM2
FLAG -1056 -192 Vin
SYMBOL cap -912 -208 R90
WINDOW 0 0 32 VBottom 0
WINDOW 3 32 32 VTop 0
SYMATTR InstName C1
SYMATTR Value {CE1}
SYMBOL cap -240 -208 R90
WINDOW 0 0 32 VBottom 0
WINDOW 3 32 32 VTop 0
SYMATTR InstName C2
SYMATTR Value {CE2}
SYMBOL cap -816 -80 R180
WINDOW 0 24 64 Left 0
WINDOW 3 24 8 Left 0
SYMATTR InstName C3
SYMATTR Value {CT1}
SYMBOL cap -640 -176 R270
WINDOW 0 32 32 VTop 0
WINDOW 3 0 32 VBottom 0
SYMATTR InstName C4
SYMATTR Value {C12}
SYMBOL cap -528 -144 R0
SYMATTR InstName C5
SYMATTR Value {CT2}
SYMBOL ind -752 -176 R0
SYMATTR InstName L1
SYMATTR Value {L1}
SYMATTR SpiceLine Rser={InductorR}
SYMBOL ind -416 -176 R0
SYMATTR InstName L2
SYMATTR Value {L2}
SYMATTR SpiceLine Rser={InductorR}
SYMBOL voltage -1072 -176 R0
WINDOW 123 24 160 Left 0
WINDOW 39 24 132 Left 0
SYMATTR Value2 AC 1
SYMATTR SpiceLine Rser=50
SYMATTR InstName V1
SYMATTR Value ""
SYMBOL res -160 -176 R0
SYMATTR InstName R1
SYMATTR Value 50
TEXT -648 -296 Left 0 !.ac lin 1024 3Meg 7.3Meg
TEXT -1064 56 Left 0 !.param InductorQ=200
TEXT -1064 96 Left 0 !.param InductorR=6.28*7.1Meg*LT/InductorQ
TEXT -528 176 Left 0 !.param CE2=120p*(1+0.05*2*(rand(x+400)-0.5))
TEXT -1064 216 Left 0 !.param C12=39p
TEXT -1064 136 Left 0 !.param LT=1.3u
TEXT -1064 256 Left 0 !.param CT 240p
TEXT -720 32 Left 0 !.step param x 0 100 1
TEXT -528 72 Left 0 !.param L1=LT*(1+0.05*2*(rand(x+100)-0.5))
TEXT -528 104 Left 0 !.param L2=LT*(1+0.05*2*(rand(x+200)-0.5))
TEXT -528 216 Left 0 !.param CT1 CT*(1+0.05*2*(rand(x+500)-0.5))
TEXT -528 256 Left 0 !.param CT2 CT*(1+0.05*2*(rand(x+600)-0.5))
TEXT -528 144 Left 0 !.param CE1=CE*(1+0.05*2*(rand(x+300)-0.5))
TEXT -1064 176 Left 0 !.param CE=120p
