Okay; I was looking for a way to just copy the dimensions, but that
will
work.
Thanks,
Leslie
On Tuesday 01 January 2013 13:48:06 Rick McGuire wrote:
> On Tue, Jan 1, 2013 at 2:13 PM, Jean-Louis Faucher
<[email protected]>wrote:
> > Maybe
> > array2 = array~copy
> > ?
> > and then you assign the values you want in each cell.
>
> You'd probably want to throw in an empty call after the copy to get it to a
> clean state.
>
> Rick
>
> > 2013/1/1 Leslie Turriff <[email protected]>
> >
> >> What is the cleanest way to create a second multi-dimension
> >> array with the
> >> same dimensions as a first array? The documentation doesn't talk much
> >> about
> >> multi-dimension arrays, and shows no examples of referencing them.
> >> I thought that array~size might give me what I'm looking for,
> >> but it looks
> >> like that won't help; the description of array~items is rather vague,
> >> but I
> >> think that its value for multi-dimension arrays is probably similar to
> >> array~size?
> >> array~last might do the trick. Can I use its value directly
> >> inthe instantiation of the new array [newArray =
> >> .array~new(old~array~last)]? Or
> >> do I have to break up the output first?
> >>
> >> Thanks,
> >> Leslie
> >>
> >>
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