Hi Mark, thanks, I never thought about that. I'll look into it right away.
Btw, today is Nov 29, 2013 ;)
Staffan
On Fri, Nov 29, 2013 at 8:53 PM, Mark Miesfeld <[email protected]> wrote:
> On Fri, Nov 29, 2013 at 11:17 AM, Staffan Tylen
> <[email protected]>wrote:
>
>
>> I'm playing around with the date() function and am trying to convert a
>> date in the format yyddd to yymmdd but I can't find a way to handle the yy
>> portion of the date. The "D" option supports the ddd portion but the result
>> shows the current year. How can I make yy be part of the calculation?
>>
>
> Hi Staffan,
>
> I'm not much help here, dates are too complex for me. If I can figure out
> today's date, I'm about at my limit.
>
> My first thought though is that the DateTime class may be of more help
> than the date() function.
>
> --
> Mark Miesfeld
>
>
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