The create method only creates the external queue, it does not create a
RexxQueue instance. The return value is just the string name of the queue
you just created, so the variable testQ is just a string object, which does
not support a linein method. Try adding this:
testQ = .rexxqueue~new('testQ')
Rick
On Fri, Feb 14, 2014 at 6:17 PM, J. Leslie Turriff <
[email protected]> wrote:
> I'm trying to use the RexxQueue utility class as documented in
> "5.4.17 The
> RexxQueue Class" of "ooRexx Documentation 4.2 | Open Object Rexx(tm)|
> Reference", but I obviously don't understand what the manual is telling me.
> Here's a testcase program:
>
> #!/usr/bin/rexx
> trace ?rnormal
> signal on syntax
>
> if .rexxQueue ~ exists('testQ') then
> .rexxQueue ~ delete('testQ')
>
> testQ = .rexxQueue ~ create('testQ')
> "/usr/bin/tree -pugshD -L 3 --noreport",
> "|/usr/bin/rxqueue testQ"
> anchor = testQ ~ linein -- <=== fails here.
> lines = testQ ~ queued
> line = .array ~ new(lines)
>
> do l = 1 to lines
> line[l] = testQ ~ linein
> end
>
> syntax:
> say errortext(rc)
>
> if .rexxQueue ~ exists('testQ') then
> .rexxQueue ~ delete('testQ')
> exit
>
> And here's what happens when I run it:
>
> 17:08:29,leslie@pinto
> ~/bin/rexx
> $testcase
> +++ "LINUX COMMAND /home/leslie/bin/rexx/testcase"
> 3 *-* signal on syntax
> +++ Interactive trace. "Trace Off" to end debug, ENTER to Continue. +++
>
> 5 *-* if .rexxQueue ~ exists('testQ')
> >>> "1"
>
> 5 *-* then
> 6 *-* .rexxQueue ~ delete('testQ')
> >>> "0"
>
> 8 *-* testQ = .rexxQueue ~ create('testQ')
> >>> "testQ"
>
> 9 *-* "/usr/bin/tree -pugshD -L 3 --noreport","|/usr/bin/rxqueue
> testQ"
> >>> "/usr/bin/tree -pugshD -L 3 --noreport |/usr/bin/rxqueue
> testQ"
>
> 11 *-* anchor = testQ ~ linein -- <=== fails here.
> 19 *-* syntax:
>
> 20 *-* say errortext(rc)
> >>> "Object method not found"
> Object method not found
>
> 22 *-* if .rexxQueue ~ exists('testQ')
> >>> "1"
>
> 22 *-* then
> 23 *-* .rexxQueue ~ delete('testQ')
> >>> "0"
>
> 24 *-* exit
>
> Leslie
>
>
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