Dear Gaby,
I saw you implemented map!$Stack as follows:
map!(f: S -> S, s: %) == -- from HOAGG
map!(f, deref s)$List(S)
s
I have two questions:
1) why didn't you say
map!(f: S -> S, s: %) == ref map!(f, deref s)$List(S)
2) isn't
map!(f: S -> S, s: %) == -- from HOAGG
map!(f, deref s)$List(S)
s
assuming that map! stores its result in s? I'm not sure whether this is ok:
pro: the documentation says:
map!(f,u) destructively replaces each element x of u by \axiom{f(x)}.
which could be interpreted as "map! stores its result in s"
con: it might well be possible to have an implementation where this is
undesirable, i.e, although one which is destructive to s, but where s
does not contain the result of map! afterwards. If I recall correctly,
sort! works that way:
(14) -> l := [1,16,81,1]
(14) [1,16,81,1]
Type: List PositiveInteger
(15) -> sort! l
(15) [1,1,16,81]
Type: List PositiveInteger
(16) -> l
(16) [1,16,81]
Type: List PositiveInteger
comments?
Martin
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