If the function a ThreadedWorker is executing raises an exception, don't
use print() as that mostly disappears. Instead, output it to the logger.
This is done using bb.mainlogger.debug directly instead of bb.debug() as
this allows us to pass the exception instance directly, which is then
incorporated into the log stream.
Signed-off-by: Ross Burton <ross.bur...@arm.com>
---
meta/lib/oe/utils.py | 3 ++-
1 file changed, 2 insertions(+), 1 deletion(-)
diff --git a/meta/lib/oe/utils.py b/meta/lib/oe/utils.py
index 238af314d1..cf65639647 100644
--- a/meta/lib/oe/utils.py
+++ b/meta/lib/oe/utils.py
@@ -508,7 +508,8 @@ class ThreadedWorker(Thread):
try:
func(self, *args, **kargs)
except Exception as e:
- print(e)
+ # Eat all exceptions
+ bb.mainlogger.debug("Worker task raised %s" % e, exc_info=e)
finally:
self.tasks.task_done()
--
2.25.1
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