Oops, let's make that example more generic(!) //=========================== lyrNum = 2; var delta = map.getNumLayers() - lyrNum;
map.raiseLayer(layer_e, -delta); map.raiseLayer(layer_b, delta); //=========================== Jason On Fri, Aug 10, 2012 at 10:26 AM, Jason Lee <[email protected]> wrote: > Don't know if it is the best solution, but I am now using > "map.raiseLayer()" like so:- > > //=========================== > lyrNum = 2; > var delta = map.getNumLayers() - lyrNum; > > map.raiseLayer(layer, -delta); > map.raiseLayer(netLayer, delta); > //=========================== > > This seems to do the trick. > > Jason > > > On Fri, Aug 10, 2012 at 9:55 AM, Jason Lee <[email protected]> wrote: > >> Hi, >> I have an OpenLayers application which initially has 4 layers, called >> (a),(b),(c) & (d). The app then allows the creation of a new layer (e) >> which I want it to "swap" places with layer (b) so that the order should be >> (a),(e),(c),(d),(b). >> >> I use the map.setLayerIndex and layer.getZIndex to try and do this but I >> realise that the layers are in a FIFO like queue, so when I temporarily >> re-assign layer (b) the other layers automatically reorder themselves to >> (a),(c),(d),(e) ...or at least that's what I think it happening. >> >> Could anyone show me how I can simply swap the z-order of 2 layers? >> >> Thanks >> >> Jason >> > >
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