You don't need p.
Patrik
Dr Stephen Henson wrote:
> Ignacio Gil wrote:
> >
> > Hello,
> > I need to transform a PKCS7* to a char* or similar, and I've done this:
> >
> > unsigned char **msg_aux;
> > msg_aux=(unsigned char **) malloc (8194); /*enough size...*/
> > i=i2d_PKCS7(p7,msg_aux);
> >
> > I've got a segmentation fault.
> > Could anybody help me?
>
> The correct way is this...
>
> int len;
> unsigned char *buf, *p;
>
> len = i2d_PKCS7(p7, NULL);
> buf = malloc(len);
> p = buf;
> i2d_PKCS7(p7, &p);
>
> Steve.
> --
> Dr Stephen N. Henson. http://www.drh-consultancy.demon.co.uk/
> Personal Email: [EMAIL PROTECTED]
> Senior crypto engineer, Celo Communications: http://www.celocom.com/
> Core developer of the OpenSSL project: http://www.openssl.org/
> Business Email: [EMAIL PROTECTED] PGP key: via homepage.
>
> ______________________________________________________________________
> OpenSSL Project http://www.openssl.org
> Development Mailing List [EMAIL PROTECTED]
> Automated List Manager [EMAIL PROTECTED]
______________________________________________________________________
OpenSSL Project http://www.openssl.org
Development Mailing List [EMAIL PROTECTED]
Automated List Manager [EMAIL PROTECTED]
