Hi Marek, I do the following:
static char *login="login"; static char *password="password"; static char *label="label"; const unsigned char *buf=NULL; strcat(&buf, login); strcat(&buf, password); strcat(&buf, label); unsigned char *m1[20]; unsigned char *m2[20]; SHA1(&buf, strlen(&buf), m1); // The output is: 3d79ad220830e96dabd6ae6f9973306df1800906 //the output of the above SHA1 will be used as an input for the SHA1 below, after concatenating it with label strcat(&m1, label); SHA1(&m1, str len(&m1), m2); I don't know why the output of the second SHA1 is not the same when I run the program several times. But I think the problem is in the m1 storing, but I don't know how to resolve that. Thanks, Best regards, On Fri, Apr 11, 2008 at 12:46 PM, <[EMAIL PROTECTED]> wrote: > Hello, > > [EMAIL PROTECTED] wrote on 04/11/2008 03:51:18 AM: > > > > Dear all, > > > > I need to call the hash function two times, in which the output of the > > first call is used as an input for the second (result = hash[hash(A > > +B) + C] > > > > The first call is ok, but when I concatenate its output to the C, I > > don't get the expected output. > > > > Did I miss something? > Expression above looks good, but there is too little information > of real implementation to say something reasonable. > > Best regards, > -- > Marek Marcola <[EMAIL PROTECTED]> > > ______________________________________________________________________ > OpenSSL Project http://www.openssl.org > User Support Mailing List openssl-users@openssl.org > Automated List Manager [EMAIL PROTECTED] > -- Badra ______________________________________________________________________ OpenSSL Project http://www.openssl.org User Support Mailing List openssl-users@openssl.org Automated List Manager [EMAIL PROTECTED]
