Why is this a problem? What is the problem? SSL and TLS are designed to abstract out underlying protocol details from the protocol client. What are you doing that requires a 1 to 1 correspondence?
-Kyle H 2008/7/27 abc_123_ok <[EMAIL PROTECTED]>: > I can't fix my problem , anybady can help me? > > ________________________________ > abc_123_ok > 2008-07-28 > ________________________________ > 发件人： abc_123_ok > 发送时间： 2008-07-25 09:35:17 > 收件人： openssl-users@openssl.org > 抄送： > 主题： Re: Re: Re: hello everyone > > Dear Victor Duchovni， > > I knew what you speak as below, > I have added the CBC padding and Mac and record head, but besides these len, > it still have 24 bytes is more. the 24 bytes is before the application > data. > > my problem still can n't be fixed. > > > ________________________________ > abc_123_ok > 2008-07-25 > ________________________________ > 发件人： Victor Duchovni > 发送时间： 2008-07-24 22:02:49 > 收件人： openssl-users@openssl.org > 抄送： > 主题： Re: Re: Re: hello everyone > > On Thu, Jul 24, 2008 at 05:10:54PM +0800, abc_123_ok wrote: > >> I want to know what the 24 byte is. > > The TLS "record layer" uses a 5 byte header. The actual data > is extended with a MAC, and encrypted which often adds CBC padding. > > You should not make any assumptions about the length of the encrypted > data on the wire, there may also be packets for renegotiation if the > client or server chooses to do that. > > -- > Viktor. > ______________________________________________________________________ > OpenSSL Project http://www.openssl.org > User Support Mailing List openssl-users@openssl.org > Automated List Manager [EMAIL PROTECTED] :��I"Ϯ��r�m���� (����Z+�K �+����1���x ��h����[�z�(����Z+� ��f�y������ �f���h��)z{,���
