> On 16 Aug 2021, at 5:58 am, Bala Duvvuri via openssl-users
> <[email protected]> wrote:
>
> We are using OpenSSl version 1.1.1d in our program and crash is being seen in
> "OPENSSL_sk_pop_free" API, we invoke this API in our certificate verification
> API. Since crash is not seen always, trying to understand from OpenSSL code,
> when can this occur?
>
> Below is the bt of the crash
>
> #0 0x0f31f438 in OPENSSL_sk_pop_free (st=0x1041de20, func=0xf34d5b0
> <X509_free>) at crypto/stack/stack.c:367
> #1 0x0f344c74 in sk_X509_pop_free (freefunc=<optimized out>, sk=<optimized
> out>) at include/openssl/x509.h:99
> #2 X509_STORE_CTX_cleanup (ctx=ctx@entry=0x1041ba70) at
> crypto/x509/x509_vfy.c:2454
> #3 0x0f344cf4 in X509_STORE_CTX_free (ctx=ctx@entry=0x1041ba70) at
> crypto/x509/x509_vfy.c:2281
The call in question frees the certificate chain built by X509_verify_cert().
sk_X509_pop_free(ctx->chain, X509_free);
That chain is owned by the X509_STORE_CTX. You probably made the
mistake of freeing it (or one of the certificates in question) yourself.
There are two functions for accessing the built chain:
STACK_OF(X509) *X509_STORE_CTX_get0_chain(X509_STORE_CTX *ctx)
{
return ctx->chain;
}
STACK_OF(X509) *X509_STORE_CTX_get1_chain(X509_STORE_CTX *ctx)
{
if (!ctx->chain)
return NULL;
return X509_chain_up_ref(ctx->chain);
}
If you call X509_STORE_CTX_get0_chain(3), you MUST NOT free the result.
If you call X509_STORE_CTX_get1_chain(3), you own the chain copy, and
should free the result when you no longer need it.
--
Viktor.
