Hello, * I'm using Zuul v3 ver.2.5.3.dev1585.
I created a job which runs following two tasks for zuul v3.[1] 1. Run tests on remote host which is created by Nodepool. (In this time, "hosts" value is "all".) 2. Run zuul_return on localhost where is zuul-executor. And, submit a URL of logs specified as "log_url" attribute to gerrit. (In this time, "hosts" value is "localhost".) In this case, task 2 won't be run if task 1 is failed. And, the below URL will be submitted to gerrit. finger://<hostname of zuul-executor>/e8ce4c7f627a43689dd9ad4ecc43c881 How do you run "zuul_return" if the test task will be failed? P.S. If I specified "ignore_errors:True" in task 1, task2 was run even if task1 was failed. But, the submitted result was "SUCCESS" in this case. [1] I refered the following suggestion. http://lists.openstack.org/pipermail/openstack-infra/2017-October/005646.html -- _/_/_/_/_/_/_/_/_/_/_/_/_/_/_/_/_/_/_/_/_/_/_/_/_/ Rikimaru Honjo E-mail:[email protected] _______________________________________________ OpenStack-Infra mailing list [email protected] http://lists.openstack.org/cgi-bin/mailman/listinfo/openstack-infra
