Here is my attempt to display the difference between two dates in the format
<days>:<Hours>:<Minutes>:<seconds>
The two dates are dt1 and dt2
If dt1 is later than dt2 then result returned as negative.
It should work for differences of +/- 99 days - to increase the range,
change '09' at the end of the first line to the size desired.
to_char(trunc(greatest(dt2,dt1) - least(dt2,dt1)) * sign(dt2 - dt1),'09') ||
':' ||
to_char(to_date(1,'J') + (greatest(dt2,dt1) - least(dt2,dt1)) ,'HH24:MI:SS')
Regards
Garry
-----Original Message-----
From: Scott Canaan [mailto:[EMAIL PROTECTED]]
Sent: 10 July 2001 15:12
To: Multiple recipients of list ORACLE-L
Subject: Re: Date / Time
Sajid,
Unfortunately, I ran into the same problem. I didn't find anything to do
it for me, either, so I had to write the pl/sql code. It is very long and
messy, but can be done. When I did it, I didn't even attempt the days
notation. Here is the code that I wrote:
date_diff := trans_cur.modified_date - last_date;
date_diff_tot := trans_cur.modified_date - first_date;
SELECT decode( trunc( date_diff * 24),0,
to_char( trunc( date_diff * 1440), 'FM90') || ':' ||
to_char( round( date_diff * 86400) - trunc( date_diff
* 1440) * 60,'FM00'),
to_char( trunc( date_diff * 24),'FM90') || ':' ||
to_char( trunc( date_diff * 1440 - trunc( date_diff *
24)
* 60),'FM00') || ':' ||
to_char( round( date_diff * 86400 - trunc( date_diff
* 1440) * 60), 'FM00')),
decode( trunc( date_diff_tot * 24), 0,
to_char( trunc( date_diff_tot * 1440),'FM90') || ':' ||
to_char( round( date_diff_tot * 86400)
- trunc( date_diff_tot * 1440) * 60,'FM00'),
to_char( trunc( date_diff_tot * 24),'FM90') || ':' ||
to_char( trunc( date_diff_tot * 1440
- trunc( date_diff_tot * 24) * 60),'FM00') || ':' ||
to_char( round( date_diff_tot * 86400
- trunc( date_diff_tot * 1440) * 60), 'FM00'))
INTO elapsed_1, elapsed_2
FROM dual;
I hope this helps.
Sajid Iqbal wrote:
> Hello All
>
> I want to display the "time elapsed" between two dates - in days, hours,
> minutes and seconds.
>
> If I do "select date1 - date2", the result is : 12.0194907
>
> Is there a function that will turn the number of days into something more
> legible? Ideally i'd like to do ;
>
> "to_char(12.0194907,'DD:HH:MI:SS')" but obviously that won't work. Is
> there a solution other than writing a complex function myself which will
> have to * by 24, / by 60 and substr etc to get the different bits of the
> number?
>
> Please CC any replies directly to me at [EMAIL PROTECTED]
>
> Thanks in advance,
> Saj.
>
> --
> Sajid Iqbal
> Database Team Leader
>
> --
> Please see the official ORACLE-L FAQ: http://www.orafaq.com
> --
> Author: Sajid Iqbal
> INET: [EMAIL PROTECTED]
>
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--
Scott Canaan ([EMAIL PROTECTED])
(716) 475-7886
"Life is like a sewer, what you get out of it depends on what you put into
it" - Tom Lehrer
--
Please see the official ORACLE-L FAQ: http://www.orafaq.com
--
Author: Scott Canaan
INET: [EMAIL PROTECTED]
Fat City Network Services -- (858) 538-5051 FAX: (858) 538-5051
San Diego, California -- Public Internet access / Mailing Lists
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