First, you should be aware that the Cost is only Oracle's best guess as to
what Access Path is faster. It's often wrong.
What version are you on? Depending on version you have several options
1. Create a histogram on the XSKSHDRS181M1 column
2. Set the optimizer_index_cost_adj equal to a value under 100. This lowers
the cost Oracle assumes an index will add. We have it set to 75 on our data
warehouse.
3. Associate the access path resulting with using the hint with the SQL (I
don't remember how to do this, but remember reading about it around a year
ago).
Good luck!
Jay Miller
-----Original Message-----
Sent: Friday, February 08, 2002 1:08 PM
To: Multiple recipients of list ORACLE-L
I have a table of 500,000 records that is analyzed and contains several
indexes that are analyzed.
Can someone explain to me why the cost without a hint is much lower than the
cost with a hint?
Using a hint is 10 times faster than without a hint even though the cost is
much higher.
Since this is a third party app, I cannot add hints. What aoptions do I
have?
select /*+ Index("ICMSSHDR" XSKSHDRS181M1) Use this index XSKSHDRS181M1 */
PKTS_ICMSSHDR from ICMSSHDR
where (FK_IX_ICMSSHDR_DELV='x' and (SHDR_DELV_WHSE_CODE<'86'));
Execution Plan
----------------------------------------------------------
0 SELECT STATEMENT Optimizer=CHOOSE (Cost=213529 Card=228346
Bytes=12102338)
1 0 TABLE ACCESS (BY INDEX ROWID) OF 'ICMSSHDR' (Cost=213529
Card=228346 Bytes=12102338)
2 1 INDEX (RANGE SCAN) OF 'XSKSHDRS181M1' (NON-UNIQUE) (Cost=2346
Card=228346)
select PKTS_ICMSSHDR from ICMSSHDR
where (FK_IX_ICMSSHDR_DELV='x' and (SHDR_DELV_WHSE_CODE<'86'));
Execution Plan
----------------------------------------------------------
0 SELECT STATEMENT Optimizer=CHOOSE (Cost=3526 Card=228346
Bytes=12102338)
1 0 TABLE ACCESS (FULL) OF 'ICMSSHDR' (Cost=3526 Card=228346
Bytes=12102338)
Thanks
John Baylis
Database Administrator
Canadian Forest Products Ltd.
Vancouver B.C. Canada
(604) 697-6476 (Office)
(604) 313-6054 (Cell)
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