Johan,

There is no need to convert sysdate to a string and back to a data.  I'm not
sure what you mean by  "calculate the previous 24 hours when a query is run
and bump the time by 6 hours".

It looks like you are trying to retrieve all records that have a date/time
within the last 18 hours - is this correct?  if so, then your query would
be:

where event_date > (sysdate + 6/24) - 1

The default date format really has nothing to do with how the dates are
stored within the database - they are all stored the same way.  This means
you can do simple date math like above.

Hope this is what you are looking for.

Tom Mercadante
Oracle Certified Professional


-----Original Message-----
Sent: Tuesday, April 09, 2002 8:13 AM
To: Multiple recipients of list ORACLE-L


I need a where clause to ACCURATELY (down to the second) calculate the
previous 24 hours when a query is run and bump the time by 6 hours
(event_date is based on GMT). The default date format has been set to
'SYYYY-MM-DD HH24:MI:SS','NLS_CALENDAR=GREGORIAN'.

I've tried the following:

" where event_date > (to_date(substr(sysdate,0,22),'YYYY/MM/DD HH24:MI:SS')
+ 6/24) - 1".

Any ideas?

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