what are the 1700 values
if the are all alphabetic and not too long you could do something like the
below though it's all getting a bit long-winded
select
chr(65+(floor((rownum-1)/676)))||chr(65+(floor((mod(rownum-1,676))/26)))||ch
r(65+(mod(rownum-1,26)))
from addresses -- any table big enough
where rownum < 26*26*26
group by
chr(65+(floor((rownum-1)/676)))||chr(65+(floor((mod(rownum-1,676))/26)))||ch
r(65+(mod(rownum-1,26)))
having
chr(65+(floor((rownum-1)/676)))||chr(65+(floor((mod(rownum-1,676))/26)))||ch
r(65+(mod(rownum-1,26))) in
('ABA','ACY','ABT'...) -- the 1700 values
minus
select code
from table
-----Original Message-----
Sent: Monday, September 23, 2002 5:28 PM
To: Multiple recipients of list ORACLE-L
Good morning list,
Environment HP-UX 11.0 Oracle 8.1.6
Can anyone help with this SQL.
I can get a result set of values from a table
that match a given list of values -
select code
from table
where code in ('A','B','C','D','E')
I can get a result set of values from a table
that do not match a given list of values -
select code
from table
where code not in ('A','B','C','D','E')
So far so good.
Now, how do I get the set of values from the list
that do NOT have a matching value in the table?
I cannot create any objects in the schema I am
working in otherwise I would create a table with
the values and do a minus, but I can't figure out
how to do it in SQL only.
Thanks in advance, folks.
Steve
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