I'm a bit confused by the default for filesperset.  I ran the following yesterday ....

run
{
allocate channel c1 device type sbt format 'df_%t_%s_%p' maxpiecesize=2048M
PARMS="SBT_LIBRARY=/opt/oracle/dbserver/9.0.1/lib/libobk.so,
ENV=(TDPO_OPTFILE=/opt/tivoli/tsm/client/oracle/bin/tdpo.opt)";
backup database;
backup current controlfile;
release channel c1;
}

There were 245 datafiles in the database.  RMAN made the following backup sets

   BS_KEY COUNT(B.FILE#)
---------- --------------
      9623             63
      9727             64
      9810             64
      9892             35
      9893              4
      9894              4
      9895              6
      9896              5
           --------------
sum                   245


As I understand it the default for filesperset is the lesser of 64 or the number of 
input files / the number of channels.
As there was only one channel I would have expected  3 backup sets of 64 files and one 
of 53 channels.

Today I ran  against  the same target database 

run
{
allocate channel c1 device type sbt format 'df_%t_%s_%p' maxpiecesize=2048M
PARMS="SBT_LIBRARY=/opt/oracle/dbserver/9.0.1/lib/libobk.so,
ENV=(TDPO_OPTFILE=/opt/tivoli/tsm/client/oracle/bin/tdpo.opt)";
allocate channel c2 device type sbt format 'df_%t_%s_%p' maxpiecesize=2048M
PARMS="SBT_LIBRARY=/opt/oracle/dbserver/9.0.1/lib/libobk.so,
ENV=(TDPO_OPTFILE=/opt/tivoli/tsm/client/oracle/bin/tdpo.opt)";
backup database skip readonly;
backup current controlfile;
release channel c1;
release channel c2;
}

There are 92 read write datafiles.  I would have expected the job to be divided into 
two backup sets with 46 files each.

Instead I got

    BS_KEY COUNT(B.FILE#)
---------- --------------
     10704              2
     10705              2
     10721              2
     10722              2
     10723              2
     10724              2
     10725              2
     10726              2
     10727              2
     10728              2
     10765             33
     10766              4
     10767              2
     10768              1
     10769              1
     10770              1
     10771              1
     10772              1
     10773              1
     10774              1
     10775              1
     10776              1
     10777              1
     10778              1
     10779              1
     10780              2
     10781              1
     10782             18
           --------------
sum                    92
-------------------------------------------------------------------------------------------------------------------------

Any guesses as to why so many backup sets are being created.

Ian MacGregor
Stanford Linear Accelerator Center
[EMAIL PROTECTED]

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Author: MacGregor, Ian A.
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