They are not likely using the same execution paths.

Try running this statement first:

alter session set events '10046 trace name context forever, level 8';

and then run your queries.

Be sure to first run the one that will return rows, in case you
need to stop the other query.

The trace file should contain both execution paths.

In general, the 'not exists' is good for queries that
are returning only a few rows from a table, as long 
as the table is properly indexed.

'not in' would be more useful where a large part
of the table is being read anyway, and an FTS is
the best execution plan.

Depending on the version of Oracle and accompanying
optimizer, the execution paths may differ.

Just for fun, try this form:

select distinct a.id
from tab a, b
where a.id = b.id(+)
and b.id is null;

Also, why are you using the 'distinct'?

Jared


On Sat, 2003-08-16 at 14:39, Sai Selvaganesan wrote:
> hi
>  
> i am trying to figure out which is a more efficient method to do an antijoin between 
> two tables. The version is 9i and optimiser is choose.stats are the lates.
>  
> here is the query with not in and not exitsts:
> case 1:
> select distinct a.id from tab a
> where a.id not in (select b.id from b)
> /
> case 2:
> select distinct a.id from tab a
> where not exists (select b.id from b where .id=a.id)
> /
>  
> the subquery returns 4.8 mill rows in the first case and the o/p never comes out in 
> the first case.
> the second case works better and gives me a result.
> but what is interesting is the explain plan is the same.
>  
> can some explain this to me? the other question i have will the second query behave 
> the same way if the sub-query returns 4.8 mill records.
> is there a better way to write this code. it is find distinct ids in tab which dont 
> exist in b.bot tables are bound to grow. at this moment tab has 10000 rows and b 4.8 
> million rows.
> thanks
> sai
>  


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Author: Jared Still
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