Ralph,

Assuming that there is no history in the BIDS table (meaning that there are
no "old" records indicating a bid recorded last year), I think the following
would work just fine.


select name
from person, 
(select distinct sid, count(*) bid_count
  from bids
  group by sid) bids
where person.sid = bids.sid
and bid_count = 3


Tom Mercadante
Oracle Certified Professional


-----Original Message-----
Sent: Monday, September 29, 2003 9:20 AM
To: Multiple recipients of list ORACLE-L


Im taking a database theory class(no I dont need help with my homework).
There is an interesting query in the book that I have never seen posed
before. The solution would be hideously slow if there was even a moderate
amount of data in the tables. How would you write it? 

Given 3 tables: and columns in the tables:

TABLE: Person
Primary Key: SID
COLUMN: NAME

TABLE: BIDS
Primary Key: BID
Foreign Key: SID
FOREIGN KEYT: BOAT_ID
Column: Date

Boat:
Primary Key: BOAT_ID
Column: Color

Find any person who has reserved all the boats. The 

I dont have the solution with me, but there is a 'NOT EXISTS', then in the
subquery there is a minus and a correlated 'where' clause.'. That query
wouldnt move.

How would you solve this? 

Also, according to the 'SQL Standard', SQL is supposed to support op codes
such as 'ALL' or 'ANY' So you can say:

Find all people who are older than any person with blue eyes. Or find all
the people who are older than 'ALL' the people with blue eyes.

Just to reiterate. Not looking for help with my homework. My professor isnt
an Oracle guy so he doesnt know.  

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